Cyberphysics

P	=	750W (0.75kW)
t	=	10 minutes per day is 10/60 (or 1/6) hours per day (1/6 x 365.25h per year) This assumes that the hours in a year is year is averaged out from the three years with 365 days and the fourth (leap year) with 366!)

E	=	P	x	t
(kWh)		(kW)		(h)

= 0.75kW x 365.25 h = 45.66 kWh
6

Cost per kWh

21p

therefore total cost 45.65625kWh x 21p/kWh
= 958.8p
= 959p (rounding to the nearest penny)
= £9.59

LOJ Dec 2000