Nuclear Radius

Q4. The radius of a nucleus, R, is related to its nucleon number, A, by the equation:

R = r0A1/3

where r0 is a constant.

The table lists values of nuclear radius for various isotopes.

 

 

Element
R/10–15m
A
R3/10–45 m3
carbon
2.66
12
18.8
silicon
3.43
28
40.4
iron
4.35
56
82.3
tin
5.49
120
165
lead
6.66
208
295

 

(a) Use the data to plot a straight line graph and use it to estimate the value of r0

Method 1

Cube each side of the equation, giving you:

R3 = r03A

You then need to calculate R3 in the table, and plot R3against A. That will give you a straight line graph (through the origin) with a gradient of r03.

calculate data for table

plot graph: units on axes scales chosen to ensure points spread across more than 50% of page in both x and y directions

plot data (lose one mark for each error)

calculation of gradient of line = 1.41 × 10–45 m3

calculation of r0 (cube root of the gradient)

quote of answer r0 = 1.1(2) × 10–15 m , given to 2 or 3 sf, with unit

Method 2

Calculate cube root of A for the table, and plot R against A1/3. That will give you a straight line graph (through the origin) with a gradient of r0.

Element
R/10–15m
A
A1/3
carbon
2.66
12
2.29
silicon
3.43
28
3.04
iron
4.35
56
3.83
tin
5.49
120
4.93
lead
6.66
208
5.93

calculate data for table

plot graph: units on axes scales chosen to ensure points spread across more than 50% of page in both x and y directions

plot data (lose one mark for each error)

calculation of gradient of line r0 = 1.12 × 10–15 m

quote of answer r0 = 1.1(2) × 10–15 m , given to 2 or 3 sf, with unit

(8 marks)

(b) Assuming that the mass of a nucleon is 1.67 × 10–27 kg, calculate the approximate density of nuclear matter, stating one assumption you have made.

Assuming that:

the nucleus is spherical OR

all nuclei have the same density OR

that total mass is equal to the mass of constituent single nuclei (ignoring the mass difference)

OR ignoring the gaps between nucleons

any one assumption

ρ = M/V

V = 4/3(πR3) - volume of a sphere

∴M = 4/3(πR3ρ)

ρ = 3/4(M/πR3)

If A = 1 then R = r0 = 1.12 × 10–15m and m = 1.67 × 10–27kg

ρ = 3/4(1.67 × 10–27/π{1.12 × 10–15}3 )

ρ = 2.8 × 1017 kg m–3

(4 marks)

(Total 12 marks)