Nuclear Radius

Q4. The radius of a nucleus, R, is related to its nucleon number, A, by the equation:

R = r0A1/3

where r0 is a constant.

The table lists values of nuclear radius for various isotopes.

 

 

Element
R/10–15m
A
R3/10–45 m3
carbon
2.66
12
18.8
silicon
3.43
28
40.4
iron
4.35
56
82.3
tin
5.49
120
165
lead
6.66
208
295

 

(a) Use the data to plot a straight line graph and use it to estimate the value of r0

Method 1

Cube each side of the equation, giving you:

R3 = r03A

You then need to calculate R3 in the table, and plot R3against A. That will give you a straight line graph (through the origin) with a gradient of r03.

calculate data for table

plot graph: units on axes scales chosen to ensure points spread across more than 50% of page in both x and y directions

plot data (lose one mark for each error)

calculation of gradient of line = 1.41 × 10–45 m3

calculation of r0 (cube root of the gradient)

quote of answer r0 = 1.1(2) × 10–15 m , given to 2 or 3 sf, with unit

Method 2

Calculate cube root of A for the table, and plot R against A1/3. That will give you a straight line graph (through the origin) with a gradient of r0.

Element
R/10–15m
A
A1/3
carbon
2.66
12
2.29
silicon
3.43
28
3.04
iron
4.35
56
3.83
tin
5.49
120
4.93
lead
6.66
208
5.93

calculate data for table

plot graph: units on axes scales chosen to ensure points spread across more than 50% of page in both x and y directions

plot data (lose one mark for each error)

calculation of gradient of line r0 = 1.12 × 10–15 m

quote of answer r0 = 1.1(2) × 10–15 m , given to 2 or 3 sf, with unit

(8 marks)

(b) Assuming that the mass of a nucleon is 1.67 × 10–27 kg, calculate the approximate density of nuclear matter, stating one assumption you have made.

Assuming that:

  • the nucleus is spherical OR
  • all nuclei have the same density OR
  • that total mass is equal to the mass of constituent single nuclei (ignoring the mass difference)

OR ignoring the gaps between nucleons

any one assumption

ρ = M/V

V = 4/3(πR3) - volume of a sphere

∴M = 4/3(πR3ρ)

ρ = 3/4(M/πR3)

If A = 1 then R = r0 = 1.12 × 10–15 mand m = 1.67 × 10–27kg

ρ = 3/4(1.67 × 10–27/π{1.12 × 10–15}3 )

ρ = 2.8 × 1017 kg m–3

(4 marks)

(Total 12 marks)