Nuclear Radius
Q2.
(a) Show that the kinetic energy of an α particle travelling at 2.00 × 107 ms–1 is 1.34 × 10–12J when relativistic effects are ignored.
m = 4 × 1.67 × 10–27 (kg)
m = 6.68 × 10–27 kg
kinetic energy = 1/2 mv2 = 0.5 × 6.68 × 10–27 × (2.00 × 107)2 = 1.34 × 10–12 J
(2 marks)
(b) Calculate the closest distance of approach for a head-on collision between the α particle referred to in part (a) and a gold nucleus for which the proton number is 79. Assume that the gold nucleus remains stationary during the collision.
loss in k.e. = gain in p.e.
1.34 × 10–12 = Q1Q2/(4πε0r) = 2e x 79e/(4πε0r) = 178e2/(4πε0r) = 178 x (1.60 × 10-19)2/(4πε0r)
r = 158 x (1.60 × 10-19)2/(4π x 8.85 × 10-12 x 1.34 × 10–12 )
r = 2.71 × 10–14 m
(4 marks)
(c) State one reason why methods other than α particle scattering are used to determine nuclear radii.
Any valid point such as:
- strong force complicates the process
- scattering caused by distribution of protons not whole nucleon distribution
- alpha particles are massive causing recoil of nucleus which complicates results
(1 mark)
(Total 7 marks)