Q11.
(a) (i) Determine the charge, in C, of a nucleus. Q = 92 × 1.60 × 10-19 = 1.47 × 10–17 C (ii) A positive ion with a nucleus has a charge of 4.80 × 10–19 C. Determine how many electrons are in this ion. number of electrons lost = magnitude of ion charge/magnitude of charge on an electron = (4.80 × 10–19 )/(1.60 × 10–19 ) = 3 number of electrons remaining on the ion= 92 – 3 = 89
(a)
(i) Determine the charge, in C, of a nucleus. Q = 92 × 1.60 × 10-19 = 1.47 × 10–17 C (ii) A positive ion with a nucleus has a charge of 4.80 × 10–19 C. Determine how many electrons are in this ion. number of electrons lost = magnitude of ion charge/magnitude of charge on an electron = (4.80 × 10–19 )/(1.60 × 10–19 ) = 3 number of electrons remaining on the ion= 92 – 3 = 89
(i) Determine the charge, in C, of a nucleus.
(ii) A positive ion with a nucleus has a charge of 4.80 × 10–19 C. Determine how many electrons are in this ion.
= magnitude of ion charge/magnitude of charge on an electron = (4.80 × 10–19 )/(1.60 × 10–19 ) = 3
(4)
(b) A nucleus may decay by emitting two – particles to form a plutonium nucleus . State what X and Y represent and give the numerical value of each. X: number of nucleons [or number of neutrons plus protons or mass number] X = 239 Y: number of protons [or atomic number] Y = 92 + 2 = 94
(b) A nucleus may decay by emitting two – particles to form a plutonium nucleus . State what X and Y represent and give the numerical value of each.
(4) (Total 8 marks)