 |
||||
    |
||||
What would be the mass of one hundred, million, million (100 000 000 000 000 = 1014) atoms of Uranium 238 (atomic mass is 238u).
|
||||
|
238 g of uranium contains NA particles = 6.02 x 1023 238 / (6.02 x 1023) g of uranium contains 1 particle therefore 238 x 1014 / (6.02 x 1023) g of uranium contains 1014 particles = 3.95 x 10-8g of uranium (39.5 ng of Uranium)
|
||||
 |
 |
|||
